Convert a string in cell into numbers.

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Riccardo Cosmai
Riccardo Cosmai el 1 de Abr. de 2017
Editada: the cyclist el 1 de Abr. de 2017
I have: X = 1x1 struct X.T = 27919x1 cell and for example X.T(1,1) = 3,7,12,16 like char. I'd like to have X.T(1,1) like 1x4 double with 4 numeric value. How can I do this? Thank you in advance
  2 comentarios
the cyclist
the cyclist el 1 de Abr. de 2017
A couple questions:
Do you mean that X.T(1,1) is a character array that includes the commas, as in
'3,7,12,16'
Or something else?
Is all of X.T like that, such that you want to convert the entire cell array from such character arrays to numeric? Or do you just want to do specific elements that you will index into?
Riccardo Cosmai
Riccardo Cosmai el 1 de Abr. de 2017
yes includes commas. And i want to for example 3 like a specific element, 7 like an other specific element,... then a row 4x1 with numeric elements

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the cyclist
the cyclist el 1 de Abr. de 2017
% Defining an example cell array that contains a character array.
a{1,1} = '3,7,12,16';
% Convert the contents of that element to a numeric array
a{1,1} = str2num(a{1,1})
  2 comentarios
Riccardo Cosmai
Riccardo Cosmai el 1 de Abr. de 2017
Thank you so much. I resolve with this:
for i=1:27919
X.T{i,1}=str2num(X.T{i,1});
end
the cyclist
the cyclist el 1 de Abr. de 2017
Editada: the cyclist el 1 de Abr. de 2017
You can do this more compactly like this:
X.T = cellfun(@str2num,X.T,'UniformOutput',false)
The reason I did not suggest this originally is that I thought you only wanted to convert individual elements, not the whole thing.

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