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derivative of bessel function of the first kind !!

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Ano
Ano el 3 de Abr. de 2017
Comentada: Feruza el 15 de Jun. de 2023
Hello! I would like to check if my implementation of the derivative of bessel function of the first kind is working properly or not , how can I check?! this is the code that I have implemented, please correct me if it is wrong!
c = sqrt(pi./(2.x));
D_bessel = c.*besselj(n-0.5,x)-c.*besselj(n+0.5,x).*(n+1)./(x);

Respuestas (2)

Morgan
Morgan el 6 de Nov. de 2022
I've found a slightly easier implementation of the derivative for you based on this link. It essentially says that
In MATLAB, this would look like
function dJndx = dbesselj(n,x)
% DBESSELJ A function that will generically calculate the
% the derivative of a Bessel function of the first
% kind of order n for all values of x.
%
% Example usage: dJndx = dbesselj(n,x);
%
% INPUT ARGUMENTS
% ================
% n Order of the Bessel function of the first kind
% x Input variable to Bessel function
%
% OUTPUT ARGUMENTS
% ================
% dJndx Derivative of nth order Bessel function of the first
% kind at all values of x
dJndx = n*besselj(n,x)./x - besselj(n+1,x);
end
Hopefully this answers your question, let me know if this helps!

Feruza
Feruza el 14 de Jun. de 2023
Is there way to compute third order derivatives of Bessel functions? I could find second order derivative from bessel equation but how to proceed with the third order derivative
  2 comentarios
Morgan
Morgan el 14 de Jun. de 2023
Should be able to do
d3Jndx = dbesselj(n,dbesselj(n,dbesselj(n,x)));
For third order derivatives with the function I wrote above.
Feruza
Feruza el 15 de Jun. de 2023
Thanks, I also used MATLAB Symbolics to get analytical formulars for derivatives:
syms nu z
b = besselj(nu,z);
db = diff(b)
bj = besselj(nu,z);
ddbj = diff(bj,z,2)
dddbj = diff(bj,z,3)

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