why does this not work ?
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for n=1:4 % size(PIDS,1);
BC = {n,4};
BC{n,1} = {PIDS{n,1}; FNS{n,1}; PPNameS{n,1}; APS{n,1}};
BC{n,2} = {PIDS{n,2}; FNS{n,2}; PPNameS{n,2}; APS{n,2}};
BC{n,3} = {PIDS{n,3}; FNS{n,3}; PPNameS{n,3}; APS{n,3}};
BC{n,4} = {PIDS{n,4}; FNS{n,4}; PPNameS{n,4}; APS{n,4}};
end
BC
5 comentarios
Jan
el 3 de Abr. de 2017
We cannot know the reason, when you do not tell us what's going wrong. Do you get an error message or do the results differ from your expectations?
Anne
el 3 de Abr. de 2017
Please, Anne, post the complete error message. We do not have crystal balls and cannot guess the reason of the problems. Show us your code and care for a copy of the complete message. Obviously there is an error in your trial "to convert BC into an empty cell" - but I neitehr understand what "converting to an empty cell" means, nor how you've tried to implement this.
Anne
el 3 de Abr. de 2017
No, a complete error message should contain the failing line also. Are you running tis in the command window? If so, create a script or even better a function. Then debugging is easier und you (and the readers) do not have to guess, where the error occurres.
I've edited my answer.
Respuestas (1)
You overwrite BC in each iteration. Perhaps you want to move the pre-allocation before the loop:
BC = cell(4, 4); % Not: {4, 4};
for n = 1:4 % size(PIDS,1);
BC{n,1} = {PIDS{n,1}; FNS{n,1}; PPNameS{n,1}; APS{n,1}};
BC{n,2} = {PIDS{n,2}; FNS{n,2}; PPNameS{n,2}; APS{n,2}};
BC{n,3} = {PIDS{n,3}; FNS{n,3}; PPNameS{n,3}; APS{n,3}};
BC{n,4} = {PIDS{n,4}; FNS{n,4}; PPNameS{n,4}; APS{n,4}};
end
"BC = {n,4}" means, that BC is set to a [1 x 2] cell array. Is this intented? Afterwards the elements {n, 1:4} are added. But the values from the former itereations are overwritten.
To get the reason of the error message, write the code in a script or better a function. Then typ this in the command window:
dbstop if error
Now run your code again until it stops at the error. Inspect the variables and the indices: At least one of the arrays has less elements than you request.
1 comentario
Image Analyst
el 3 de Abr. de 2017
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