Replacing each array element with a series of values
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Varun Nair
el 25 de Abr. de 2017
Comentada: Varun Nair
el 29 de Abr. de 2017
Hi, I have a a 1 x N matrix of numbers. For example, a matrix T:
T = [1 4 7]
I would like to convert T to the new matrix as follows:
T_new = [1 2 3 4 5 6 7 8 9]
Basically, each element of T is replaced by an arithmetic series of 3 values with that element as the starting element and common difference = 1.
I tried
T_new = [T:T+3];
But it only updates the first element (I get T_new = [1 2 3 4]). Is there any quick way to do this without using a for loop ?
Thanks.
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Respuesta aceptada
Stephen23
el 25 de Abr. de 2017
>> T = [1,4,7];
>> cell2mat(arrayfun(@(n)n+(0:2),T,'uni',0))
ans =
1 2 3 4 5 6 7 8 9
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Más respuestas (2)
Andrei Bobrov
el 25 de Abr. de 2017
Editada: Andrei Bobrov
el 25 de Abr. de 2017
T_new = reshape(T(:)' + (0:2)',1,[])
3 comentarios
Andrei Bobrov
el 26 de Abr. de 2017
You are using an older version of MATLAB.
Variant for you:
T_new = reshape(bsxfun(@plus,T(:)',(0:2)'),1,[])
dbmn
el 25 de Abr. de 2017
One possible solution would be:
0. having
T = [1 4 7];
1. create a temporary matrix T_temp that looks like (this could be done in a loop very easily)
T_new = [1 2 3;
4 5 6;
7 8 9 ];
2. then reshape that matrix using
T_new=reshape(T_tmp', 1, numel(T_tmp));
1 2 3 4 5 6 7 8 9
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