How can I use a filter in a parfor with the more numerically stable z,p,k?
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Gordon
el 26 de Abr. de 2017
Comentada: Gordon
el 28 de Abr. de 2017
Hello,
I would like to use a filter in a parfor loop. Using [b,a] coefficients there is no problem. Because of a better stability I have to use the [z,p,k] coefficients. It perfectly works in a for loop. However, in a parfor loop the error massage "Not enough input arguments." appears. Does anyone know a workaround?
Here is a little example: Anything works but the last loop!
% Signal
x = sin(0:pi/1000:10*pi);
% Filter properties
N = 1;
fc = 1/(2*pi);
fs = 1000/pi;
Wn = fc/(fs/2);
ftype = 'low';
% Transfer Function design
[b,a] = butter(N,Wn,ftype);
% Zero-Pole-Gain design
[z,p,k] = butter(N,Wn,ftype);
[sos,g] = zp2sos(z,p,k);
hd = dfilt.df2tsos(sos, g);
%%Loops
for n=1:2
y = filter(b,a,x);
end
parfor n=1:2
y = filter(b,a,x);
end
for n=1:2
y = filter(hd, x);
end
parfor n=1:2
y = filter(hd, x);
end
2 comentarios
Respuesta aceptada
Aniruddha Katre
el 26 de Abr. de 2017
Modifying the parfor loop as follows seems to resolve the error. The filter object was causing the error to occur for some reason, but creating the filter object on each worker separately fixes it.
parfor n=1:2
hd = dfilt.df2tsos(sos, g);
y(n,:) = filter(hd, x);
end
2 comentarios
Edric Ellis
el 27 de Abr. de 2017
There's an underlying problem sending objects of type dfilt.df2tsos into parfor loops. An additional workaround you can use to avoid re-creating the object on each iteration is:
hdc = parallel.pool.Constant(hd);
parfor ...
... = filter(hdc.Value, ...);
end
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