use LUT holding non integer numbers

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TZ
TZ el 26 de Abr. de 2017
Comentada: TZ el 27 de Abr. de 2017
Hi, i have a matrix of integers of values 0:200 and i have a LUT vector with 201 elements. i wanted to use the intlut function to insert the LUT values into the matrix, but the problem is that this funcrion restrict the LUT vector to be uint8/16 where my values are floating points. so basically i want to convert [1, 2, 3...] to [0.234, 4.323, ..] with the same logic of the intlut function that cell with value 4 will get the 4th calue in the LUT vec. is there another function that enables the LUT vector to be non int8? thanks

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Jan
Jan el 26 de Abr. de 2017
LUT = rand(1, 201);
Data = randi([0, 200], 32, 32);
Result = LUT(Data + 1);
  3 comentarios
Jan
Jan el 27 de Abr. de 2017
There is no LUT function. LUT is a simple vector here and the look-up process is standard indexing.
TZ
TZ el 27 de Abr. de 2017
oh.. feel so stupid, i understand what you did, thanks.

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