How to find which column in a matrix/array has a nonzero value?

I am given a matrix:

x = zeros(6,7)

which can have one random nonzero value in the sixth row and I need to be able to detect which column has this nonzero value.

I have tried to use

[row,col] = find(x)

but this does not create a "col" variable that I am able to use in an "if" statement in the function I am writing. Is there a way to find which column has this nonzero value and set the number of the column as a variable. Any help is appreciated.

[Joseph Cheng]

that should be working. to have it clearer can you explain what you're doing with x because

 x = zeros(6,7)
x(2,3)=4;
[row col]= find(x)
[row1 col1]= find(x(:))

works even if you accidently made x a 1xN or Nx1 array

Answer 1

[James Tursa]

column_number = find(x(6,:));  % <-- search the 6th row only

However, why didn't the "col" variable in your attempt work for you? It would give the same result as the above.