How to make a DropDown function control the visibility of a spinner in App designer

Hi,

I am New to App Designer and i would like to make one item in the DroppDown function to make a spinner visible. Is this possible? What I have tried so far is this:

            Value= app.InstrumentDropDown.Value;
            if Value==1
              app.AntalldypSpinner.Visible='off'
            elseif Value==2
                     app.instrument='D';
                     app.AntalldypSpinner.Visible='on'
            elseif Value==3
                     app.instrument='D';
                     app.AntalldypSpinner.Visible='off'
            elseif Value==4
                    app.instrument='R';
                    app.AntalldypSpinner.Visible='off'
            end

but this only make the spinner disappear and it never shows up again. Can someone help me?

Answer 1

[Tushar Upadhyay]

The app.InstrumentDropDown.Value might be giving value in "char" instead of numeric. Make sure that the value is numeric. If it is a char then change the If statement as below:

if Value=='1' app.AntalldypSpinner.Visible='off'

If that does not work, then add the debug point in the function and see if it is going into the appropriate conditional statement.