how to multiple elements in arrays together
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For a class project I have been tasked with writing a code that will tell me the optimal dimensions to disperse heat from a wall with a square number of pins. I am very new to matlab ( I am a cc transfer student and havent yet taken the matlab course at my college). My code runs but I need it to run through each dimension against another. My code runs them in parallel currently. I tried running multiple for loops to no avail. Here is the code:
%clear all
clear all; close all; clc;
%theta_w = dT
dT = 45;
%h1 and h2 for both cases
h1 = 8;
h2 = 20;
I = input ('heat transfer coefficient of 8 or 20?\n');
if (I < 9)
h=h1;
elseif (I > 9)
h=h2;
end
%k of aluminum
k = 204;
%Area of wall, diameter of fin, length of fin/corrected lengh of fin, and #
%of fins all variables
syms Aw d L Lc nFin;
for nFin = [1 4 9 16 25 36 49 64 81 100]
d = 0.001:.001:.05;
L = 0.001:.001:.05;
Aw = 0.01:.01:.5;
%corrected length eqn
Lc = L + d./4;
%area of fin
Af = (pi./4).*(d).^2;
%perimeter of fin
P = pi.*d;
% fin convection term m
m = ((h.*P)./(k.*Af)).^0.5;
%tot convection
q = dT.*h.*(Aw-(Af.*nFin)) + dT.*nFin.*tanh(m.*Lc).*(h.*k.*P.*Af).^0.5 ;
%fin convection
b = dT.*nFin.*tanh(m.*Lc).*(h.*k.*P.*Af).^0.5;
%wall convection
a = dT.*h.*(Aw-(Af.*nFin));
T1=table(nFin);
T2=table(a,b,q);
end
I need the code to output a and b for each d vs each L vs each Aw. Any help is much appreciated.
2 comentarios
Stephen23
el 30 de Mayo de 2017
@jourdan joyner: please do not delete your questions like that. Our volunteer efforts are open for everyone to utilize, but when you delete the question you unilaterally decide to treat us as your own personal consulting service, to be discarded at whim. It is not appreciated.
Rena Berman
el 5 de Jun. de 2017
(Answers Dev) Restored edit
Respuestas (1)
Andrei Bobrov
el 21 de Mayo de 2017
Editada: Andrei Bobrov
el 22 de Mayo de 2017
dT = 45;
hh = [8;20];
I = input ('heat transfer coefficient of 8 or 20?\n');
h = hh(ceil(I/9));
k = 204;
d = 0.001:.001:.05;
L = 0.001:.001:.05;
Aw = 0.01:.01:.5;
nFin = [1 4 9 16 25 36 49 64 81 100];
Lc = L + d/4;
Af = pi/4*d.^2;
P = pi*d;
m = (h*P./(k*Af)).^0.5;
b = dT*nFin(:).*tanh(m.*Lc).*(h*k*P.*Af).^0.5; % MATLAB >= R2016b
a = dT*h*(Aw-(Af.*nFin(:))); % MATLAB >= R2016b
b = nFin(:)*(dT*tanh(m.*Lc).*(h*k*P.*Af).^0.5);% MATLAB <= R2016a
a = dT*h*bsxfun(@minus,Aw,nFin(:)*Af); % MATLAB <= R2016a
ADD after jourdan's comment in my answer
d0 = 0.001:.001:.05;
L0 = 0.001:.001:.05;
Aw0 = 0.01:.01:.5;
nFin0 = [1 4 9 16 25 36 49 64 81 100];
n = numel(d0)^3*numel(nFin0);
Aw = zeros(n,1);
L = zeros(n,1);
d = zeros(n,1);
nFin = zeros(n,1);
dT = 45;
hh = [8;20];
I = input ('heat transfer coefficient of 8 or 20?\n');
h = hh(ceil(I/9));
k = 204;
[Aw(:),L(:),d(:),nFin(:)] = ndgrid(Aw0,L0,d0,nFin0);
Lc = L + d/4;
Af = pi/4*d.^2;
P = pi*d;
m = (h*P./(k*Af)).^0.5;
b = dT*nFin.*tanh(m.*Lc).*(h*k*P.*Af).^0.5;
a = dT*h*(Aw-(Af.*nFin));
1 comentario
jourdan joyner
el 21 de Mayo de 2017
Editada: jourdan joyner
el 21 de Mayo de 2017
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