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How to count frequency of non zero elements col wise

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Vishal Sharma
Vishal Sharma el 30 de Jun. de 2017
Comentada: Stephen23 el 30 de Jun. de 2017
I have a matrix
A = [
1 2 3 0 0;
2 2 0 2 1;
1 0 2 3 1]
I want to count column wise frequency of occurrence of all non zero numbers, i.e. 1, 2, 3 So as to get result in form of
First Col 1 (2) 2(1) 3(0)
Second Col 1(0) 2(2) 3(0)
Third Col 1(0) 2(1) 3(1)
Forth Col 1(0) 2(1) 3(1)
Fifth Col 1(2) 2(0) 3(0)

Respuesta aceptada

Stephen23
Stephen23 el 30 de Jun. de 2017
Editada: Stephen23 el 30 de Jun. de 2017
>> [N,C] = hist(A,0:3);
>> Z = N(C~=0,:).'
Z =
2 1 0
0 2 0
0 1 1
0 1 1
2 0 0
  2 comentarios
Jan
Jan el 30 de Jun. de 2017
Editada: Jan el 30 de Jun. de 2017
What a pitty that hist is "not recommended" anymore. Do you knwo a method to process the matrix directly using the modern histcounts or histogram? I miss hist and histc.
But it is still working and nicer than the loop: +1
Stephen23
Stephen23 el 30 de Jun. de 2017
@Jan Simon: as I only have access to older MATLAB versions this topic has not yet come up for me... and why they needed to be replaced is not really very clear to me either.

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Más respuestas (1)

Jan
Jan el 30 de Jun. de 2017
Editada: Jan el 30 de Jun. de 2017
A = [1 2 3 0 0; ...
2 2 0 2 1; ...
1 0 2 3 1];
nCol = size(A, 2);
Edges = [unique(A(A ~= 0)); Inf];
Result = struct('N', cell(1, nCol));
for k = 1:nCol
Result(k).N = histcounts(A(:, k), Edges);
end
Or
Result = zeros(numel(Edges) - 1, nCol);
for k = 1:nCol
Result(:, k) = histcounts(A(:, k), Edges);
end

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