Electrical Resistance - Left Division Method
5 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I'm having some trouble with an assingment using the left divison method. The examples I've been given in my text books are rather confusing, and I need some help.
I have been given three equations of Kirchoff's Voltage Law:
v - R2i2 - R4i4= 0
-R2i2 + R1i1 + R3i3 = 0
-R4i4 - R3i3 + R5i5 = 0
Now I know that I need to rearrange these so that they are "in order":
R2i2 + R4i4 = v
R1i1 - R2i2 + R3i3 = 0
-R3i3 - R4i4 + R5i5 = 0
I've also been given 4 equations for the conservation of charge at my nodes:
i6 = i1 + i2
i4 = i2 + i3
i1 = i3 + i5
i6 = i4 + i5
I don't understand what to do. Why can't I just put the given equations into a matrix and do the divison? That would look something like:
R=[1 5 2 10 5]*1000;
v1=100;
A1=[0 R(2) 0 R(4) 0 0];
A2=[R(1) -R(2) R(3) 0 0 0];
A3=[0 0 -R(3) -R(4) R(5) 0];
A=[A1;A2;A3];
b=[v1;0;0];
current=A\b
0 comentarios
Respuestas (1)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!