3D Rotation Matrix
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Hi all, I'm new here and am trying to obtain a 3D rotation matrix.
Currently, I have a set of n points: (x1,y1,z1), (x2,y2,z2)...(xn,yn,zn)
from which I have designated one particular point as the origin, and obtained an x'- and y'- vector, based on some features. It is unimportant, for this question, how I chose my origin and got the x'- and y' vector. From the x'- and y' vector, I can also obtain the z'-vector by taking cross product of x' and y'.
Now, I would like to rotate all these points about the origin I have defined, such that the x'-, y'- and z'- vectors are in line with the x-, y- and z- axes respectively.
Hence, I am looking for a 3x3 rotation matrix, R, that can be applied to all points such that:
Transformed (x,y,z) = R * Original (x,y,z)
An example of the vectors to be mapped would be say:
x': [-0.2831, -0.9246, 0.2548]' to be mapped to x: [1 0 0]
y': [0.9242, -0.1919, 0.3303]' to be mapped to y: [0 1 0]
z' will be mapped automatically if the above 2 are satisfied.
Thank you for your help!
1 comentario
Walter Roberson
el 24 de Jul. de 2017
Editada: Walter Roberson
el 24 de Jul. de 2017
Duplicates https://www.mathworks.com/matlabcentral/answers/349968-3d-rotation-matrix but this one appears to have been updated so I have closed that.
Respuesta aceptada
Más respuestas (1)
Herve Hugonnet
el 20 de Jun. de 2019
The simplest if you do not have the phase array system toolbox is to define anonymous functions :
rotx = @(t) [1 0 0; 0 cos(t) -sin(t) ; 0 sin(t) cos(t)] ;
roty = @(t) [cos(t) 0 sin(t) ; 0 1 0 ; -sin(t) 0 cos(t)] ;
rotz = @(t) [cos(t) -sin(t) 0 ; sin(t) cos(t) 0 ; 0 0 1] ;
1 comentario
Alec
el 23 de Oct. de 2019
Thanks for this
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