how to split values in a cell

Hi!
I have 'out' (attached) and I want to divide the phrases in the first columns based on the
numerical value in the second columns.
I want to obtain three arrays: in the first I want to put the phrases with numerical value
in the second columns <0, in the second I want to put the phrases with numerical value
in the second columns = 0 and in the third I want to put the phrases with numerical value
in the second columns >0
Can you help me?

2 comentarios

Shivam Raikundalia
Shivam Raikundalia el 28 de Jul. de 2017
Editada: Shivam Raikundalia el 28 de Jul. de 2017
Hello,
So if you do not know how large your 3 arrays are going to be and you want them to be exact size I suggest you do something like this:
firstarray={};
secondarray={};
thirdarray={};
for i=1:size(out,1)
if out{i,2}<0
firstarray{end+1}=out(i,1);
elseif out{i,2}==0
secondarray{end+1}=out(i,1);
else
thirdarray{end+1}=out(i,1);
end
end
This method is a little slow however since one of the arrays change size on every iteration. Hope this helps!
elisa ewin
elisa ewin el 31 de Jul. de 2017
thanks, it runs and it's helpful

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Respuestas (1)

Star Strider
Star Strider el 28 de Jul. de 2017

0 votos

If you have R2015b or later, use splitapply:
D = load('matlab.mat');
out = D.out;
[G, ID] = findgroups([out{:,2}]);
Result = splitapply(@(x){x}, out(:,1), G');

2 comentarios

elisa ewin
elisa ewin el 31 de Jul. de 2017
The code gives an error:
Undefined function 'findgroups' for input arguments of type 'double'.
Walter Roberson
Walter Roberson el 31 de Jul. de 2017
Editada: Walter Roberson el 31 de Jul. de 2017
As Star Strider indicated, findgroups requires R2015b or later.

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