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Where is the issue in my "while" statement?

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Geo
Geo el 29 de Jul. de 2017
Respondida: Teja Muppirala el 30 de Jul. de 2017
I want to evaluate the first integer evenly divisible by 3 and 5 using a Matlab code. My attempt is the following:
n=1;
while mod(n,5)~=0 && mod(n,3)~=0
n=n+1;
end
n
I'm new to Matlab and wondering where the issue here is. The code returns n=3 for some reason. I also want to extend this to find the first number evenly divisible by 1-10, for which I wrote the following while loop which also did not return the expected value. Where is my error?
n=1;
while mod(n,1:10)~=0
n=n+1;
end
n
Thank you.
  3 comentarios
Geo
Geo el 29 de Jul. de 2017
Editada: Geo el 29 de Jul. de 2017
Revision also not working as expected:
n=1;
for k=1:10
while mod(n,k)~=0
n=n+1;
end
end
n
Walter Roberson
Walter Roberson el 29 de Jul. de 2017
found_solution = false;
n = 0;
while ~found_solution
n = n + 1;
found_solution = true;
for k = 1 : 10
if mod(n,k) ~= 0
found_solution = false;
break;
end
end
end
n

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Respuestas (2)

the cyclist
the cyclist el 29 de Jul. de 2017
Editada: the cyclist el 29 de Jul. de 2017
In your second case, you are doing
mod(1,1)
then
mod(2,2)
then
mod(3,3)
and so on, because you are always incrementing n right along with k. Those mod functions are always equal to zero, so they always satisfy the while condition, so you get to n = 10.

Teja Muppirala
Teja Muppirala el 30 de Jul. de 2017
You were on the right track. This gives 2520:
n=1;
while any( mod(n,1:10)~=0 )
n=n+1;
end
n
When your conditional has more than one element, all of them must be true for it to evaluate as true. This will return 'B' and 'C'.
if [1 1 1 0]
disp('A')
else
disp('B')
end
if [1 1 1 1]
disp('C')
else
disp('D')
end

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