Subtracting Row and column vectors
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I need to subtract vectors of different dimensions, "A" with dimension of (1x91)double and "B" with dimension of (60x1) double. In addition, there are two more vectors "C" with dimension of (1x119) double and "D" with dimension of (119x1) double.
How can I get (X=A-B) and (Y=C-D) in such cases?
2 comentarios
Akira Agata
el 13 de Ag. de 2017
What do you mean by 'X=A-B'?
X(1) = A(1) - B(1), ..., X(60) = A(60) - B(60) ?
If so, what about X(61) to X(91) ?
I need the detailed definition of your calculation rule of 'A-B' and 'C-D'.
Respuestas (2)
Stephen23
el 13 de Ag. de 2017
Editada: Stephen23
el 13 de Ag. de 2017
One simple solution that does not require knowing anything about the sizes of the vectors:
>> A = randi(9,1,9)
A =
1 3 4 3 2 8 4 8 4
>> B = randi(9,6,1)
B =
7
4
8
7
4
2
>> C = diag(bsxfun(@minus,A,B))
ans =
-6
-1
-4
-4
-2
6
For newer MATLAB versions with implicit expansion:
diag(A-B)
Note that this is not particularly memory efficient so don't use this with large vectors!
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Akira Agata
el 17 de Ag. de 2017
I think the following would be one possible solution. By using zero-padding and transpose, I have adjusted A and B, C and D, to the same size.
%%Example of your data
A = rand(1,91);
B = rand(60,1);
% Adjut B to a row vector with the same length with A by zero padding
B1 = [B',zeros(1, length(A) - length(B))];
% Calculate X = A - B
X = A - B1;
%%Example of your data
C = rand(1,119);
D = rand(119,1);
% Adjust D to a row vector with the same length with C
D1 = D';
% Calculate Y = C - D
Y = C - D1;
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