BInary matrix multiplication

Hii,
I am trying to multiply two matrices defined as follows:
U = [1 1 1 1 0 0 0 0 0 1 1];
G = [0 1 0 1 1 0 0 0 0 0 0 0 0 0 0
0 0 1 1 0 1 0 0 0 0 0 0 0 0 0
0 1 1 0 0 0 1 0 0 0 0 0 0 0 0
0 1 1 1 0 0 0 1 0 0 0 0 0 0 0
1 0 0 1 0 0 0 0 1 0 0 0 0 0 0
1 0 1 0 0 0 0 0 0 1 0 0 0 0 0
1 0 1 1 0 0 0 0 0 0 1 0 0 0 0
1 1 0 0 0 0 0 0 0 0 0 1 0 0 0
1 1 0 1 0 0 0 0 0 0 0 0 1 0 0
1 1 1 0 0 0 0 0 0 0 0 0 0 1 0
1 1 1 1 0 0 0 0 0 0 0 0 0 0 1];
Here U is a matrix of size 1*11 whereas G is a matrix of size 11*15. I have no idea of how to do binary multiplication any suggestions in this regard??
Thanks for you help.

Respuestas (1)

Walter Roberson
Walter Roberson el 15 de Abr. de 2012

0 votos

7 comentarios

Dyno
Dyno el 15 de Abr. de 2012
Dear Sir,
Thanks for your reply. I really cant figure out the binary multiplication code out of it.
Dyno
Dyno el 15 de Abr. de 2012
This simple code seems to work for binary multiplication:
V = mod(double(U)*double(G),2)
Walter Roberson
Walter Roberson el 15 de Abr. de 2012
See Derek's MMBool routine in the above Question.
NGUYEN Duy Ngan
NGUYEN Duy Ngan el 29 de Abr. de 2014
Thank you very much Dyno.
Chris Volpe
Chris Volpe el 23 de Ag. de 2016
The "mod 2" part is appropriate only if boolean addition is defined as an exclusive-or operation. In most contexts it should be ordinary "or". I would do this as:
V = logical(double(U)*double(G))
Onyekachi Ukeje-Eloagu
Onyekachi Ukeje-Eloagu el 1 de Oct. de 2016
I tried using the "mod 2" and "logical" with some problems I am working on. I am not sure what you are referring to when you talk about the boolean addition being defined as an exclusive-or, but the "mod 2" gives the correct answer and "logical" does not
Walter Roberson
Walter Roberson el 1 de Oct. de 2016
Onyekachi Ukeje-Eloagu: in your situation, should boolean 1+1 be equal to 1 ("or") or should it be equal to 0 ("exclusive or") ?

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