Vectorised cell search and logical indexing

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Joshua
Joshua el 21 de Sept. de 2017
Editada: Cedric el 21 de Sept. de 2017
Hello, I would like to know if there is a vectorised/cellfun/better approach to the loop below:
% Find Key 4 in block_new{:}(1,1)
Key4 = '=x';
index4 = cellfun(@(x)regexp(x, Key4), block_new, 'UniformOutput', false);
Logic = false(length(index4),1);
for i = 1 : length(index4)
Logic(i) = ~isempty(cell2mat(index4{i}(1,1)));
end
index4 = Logic;
block_set = block_new(:,index4);
Where the cells in the 1 X m cell array, block_new are in themselves cell arrays of various sizes.
I have already tried the following:
find(~cellfun(@isempty,index4{:}(1,1)))
Thanks in advance.
  3 comentarios
Joshua
Joshua el 21 de Sept. de 2017
Yes. A typical example, let's say block_new{i} would contain:
block_new{i}(1,1) -> String
block_new{i}(1,2:n} -> String of comma delimited doubles
Jan
Jan el 21 de Sept. de 2017
~isempty(cell2mat(index4{i}(1,1)));
If the output of cell2mat is empty, the cell must have been empty already. What about:
~isempty(index4{i}{1})
instead?
Please post a relevant input array.

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Respuestas (1)

Jos (10584)
Jos (10584) el 21 de Sept. de 2017
regex can work on a cell array of strings directly:
block_new = {'abcd=x','abcd','a=xbc=x'}
index4 = regexp('block_new','=x')
  3 comentarios
Jos (10584)
Jos (10584) el 21 de Sept. de 2017
Some cells are cell array of strings themselves? Kind of complicated data structure ...
Cedric
Cedric el 21 de Sept. de 2017
Editada: Cedric el 21 de Sept. de 2017
As mentioned by Jan, it would be simpler if you would attach a sample data set. Also, if you could describe in words what you are trying to achieve, that could help because you are doing a lot of operations that seem unnecessary (but that may in fact be necessary depending the final purpose).

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