reshape a matrix from the text

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yousef albah
yousef albah el 23 de Sept. de 2017
Editada: Stephen23 el 23 de Sept. de 2017
I am trying to reshape a matrix from the text file to 45x50 , but when i do the reshape it shows that the number of the elements should not be changes. is there any problem with my coding?
% fileid = fopen ('2016 Sept 7 - Vortex 1_0001')
x = textscan (fileid, '%n %n %n %n','headerlines',3,'delimiter',',')
cc = reshape (x, 44,45)

Respuestas (2)

Stephen23
Stephen23 el 23 de Sept. de 2017
Editada: Stephen23 el 23 de Sept. de 2017
A simple way to get the numeric data in one array is to use textscan's option 'CollectOutput':
[fid,msg] = fopen(...,'rt');
assert(fid>=3,msg)
opt = {'HeaderLines',3, 'Delimiter',',', 'CollectOutput',true};
C = textscan(fid,'%n%n%n%n', opt{:});
fclose(fid);
M = C{1};
Note that in this code I display the error message if fopen can't open the file, and also put the textscan options into a cell array to make them easier to keep track of.

Cedric
Cedric el 23 de Sept. de 2017
Editada: Cedric el 23 de Sept. de 2017
The output of TEXTSCAN is a row cell array with 4 cells and each one of them contains a numeric array (column vector) of 2250 values.
>> class( x )
ans =
cell
>> size( x )
ans =
1 4
>> class( x{1} )
ans =
double
>> size( x{1} )
ans =
2250 1
It is difficult to guess what you want to achieve with the reshape, but you probably want to merge the content of all cells into a 2250x4 numeric array first:
>> data = [x{:}] ;
>> class( data )
ans =
double
>> size( data )
ans =
2250 4
where x{:} is a comma-separated list (CSL), [..] is a concatenation, and [x{:}] is equivalent to [x{1},x{2},x{3},x{4}].
  2 comentarios
Stephen23
Stephen23 el 23 de Sept. de 2017
Or just set textscan's option 'CollectOutput' to true.
Cedric
Cedric el 23 de Sept. de 2017
Stephen, move this as an answer and I vote for it ;-)

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