How do I create a sequence which goes from 1 to .000001?

How do I create a sequence which will go from 1 to .000001 looking like this:

1.0  0.1  .01  .001  .0001  .00001  .000001

It seems simple and I've tried so many different answers but nothing worked. I tried

1:-.1:0, 1:-.01:0,

amongst many other ways turned out to be duds.

[per isakson]

• Homework?
• "I've tried so many different answers but nothing worked" Show us one or two of the most promising and we might to able to improve on them.

[John Smith]

It's not a hw question, its a review question for a test. 1:-.1:0 1:-.01:0 linspace(1,0,6)

I would think these solutions would work. An example above this question which I had gotten correct was: 7,13,19......37,43,49 The command I entered was 7:6:49

^ that is correct because if you enter that in MatLab, you can obviously see it is correct.

Answer 1

[Jan]

The power operator is expensive. It is more efficient to use

cumprod(repmat(0.1, 1, 6))

If this is a homework, I leave the last step up to you.

[EDITED] What about:

10 .^ (0:-1:-6)

[John Smith]

I posted above, we have not learned that command in our class. This is a review question, not a hw question. A previous example which I had gotten correct and makes sense is: Display how to get the following in MatLab: 7,13,19......37,43,49 The command I entered was: 7:6:49

I believe the answer is supposed to be something along those lines. The code you had suggested is something we have not learned yet so far this semester.

[Jan]

See [EDITED] in my answer.

[John Smith]

Yes, this worked and was along the lines of what I was supposed to get. Thanks Jan, if you don't mind me asking, how is that explained in matlab? Meaning, what is happening to make the outcome 1, .1, .01 etc. I believe I have the first part but lose it after the second part. 10^0 is 1, but if you -1 the answer would then be 0.

[Jan]

 but if you -1 the answer

It is a bold speculation that a 1 is subtracted from 10^0 here. Split the expression into parts, to understand it:

(0:-1:-6)

This part is included in parenthesis, such that it is evaluated at first. You have learned something about the colon operator already: "a:b:c" means: start at a and add b until c is reached. This works with a negative b also.

The second part is 10 .^ .... "^" is the power operation, and ".^" means, that it is applied elementwise. Without the dot it would be a matrix operation.

Finally you get:

10 .^ [0,-1,-2,-3,-4,-5,-6]

or equivalently:

[10^0, 10^-1, 10^-2, ... 10^-6]