reshaping cell containing double arrays

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MiauMiau
MiauMiau el 10 de Oct. de 2017
Editada: Guillaume el 10 de Oct. de 2017
Hi,
I have (as an example) the following cell array:
test =
1×4 cell array
[40×1 double] [40×1 double] [40×1 double] [40×1 double]
I want test to be a 1 x 1 cell, containing the double arrays (from left to right) as one double array of dimension 160 x 1. reshape(test,[160,1]) does not work directly here. What can I do?

Respuestas (3)

KSSV
KSSV el 10 de Oct. de 2017
Editada: KSSV el 10 de Oct. de 2017
test = cell(1,4) ;
for i = 1:4
test{i} = rand(40,1) ;
end
iwant = cell2mat(test) ;
iwant = {iwant(:)} ;
  2 comentarios
MiauMiau
MiauMiau el 10 de Oct. de 2017
Is there no quicker way than looping?
Guillaume
Guillaume el 10 de Oct. de 2017
The loop is only to build the demo data.

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Guillaume
Guillaume el 10 de Oct. de 2017
That's because what you want is not reshaping but a concatenation. (The matrices may not be contiguous in memory):
test = [test{:}]
  2 comentarios
MiauMiau
MiauMiau el 10 de Oct. de 2017
That is giving me a 40x4 matrix...?!
Guillaume
Guillaume el 10 de Oct. de 2017
Editada: Guillaume el 10 de Oct. de 2017
Oh yes, your vectors are column vectors. Concatenate them vertically then:
test = vertcat(test{:})

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KL
KL el 10 de Oct. de 2017
Editada: KL el 10 de Oct. de 2017
test = cell2mat(test');
this?

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