How to convert an arbitrary rational to binary digits?

I have a number n1/n2, where n1 and n2 are integers. I would like to convert to base-2 and get the digits in order.

Answer 1

[Walter Roberson]

bits = reshape((dec2bin(sscanf(num2hex(double(n1)/double(n2)),'%8x'),32) - '0').',1,[]);

... under at least one reasonable interpretation of what "bits" are appropriate.

For example, if n1 = 1 and n2 = 18446744073709551615 then one exact binary representation is an infinite repeating sequence of sixty-three 0's followed by a 1...

Answer 2

[KL]

 dec2base(your_number,2)

read the documentation here: https://de.mathworks.com/help/matlab/ref/dec2base.html

[Mr M.]

but I need the digits, not the number

[KL]

dec2base(your_number,2)-'0'

[Walter Roberson]

dec2base is only for positive integers.

Answer 3

[Lai Yit Ming]

Binary Converter Program - Write a program to accept a single binary number of up to 8 bits and display the equivalent in decimal. Using matlab

[Walter Roberson]

that does not appear to be a solution for the Question that was asked.