Repeat row of a matrix

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dan berkowitz
dan berkowitz el 22 de Oct. de 2017
Comentada: Cedric el 23 de Oct. de 2017
Hi,
I have a 3x1 array, a = [1 2 3]', and B, a 3x2 matrix.
How can I create C, a 6x2 matrix, whose first row is the same as B and repeated once [a(1)], the second row is the second row of B repeated twice [a(2)], and the third row is the third row of B repeated three times [(a(3)]? I'm trying to use the repelem function but am a bit stuck...Do I have to loop to do this, or is there another way?
Any help would be appreciated. Thx in advance,
DB

Respuesta aceptada

Cedric
Cedric el 22 de Oct. de 2017
Here is one way to achieve it. If
>> a = [1;2;3] ;
>> B = randi( 10, 3, 2 )
B =
3 10
6 2
10 10
Then
>> C = arrayfun( @(k)repelem(B(k,:),a(k),1), 1:numel(a), 'UniformOutput', false ) ;
>> C = vertcat( C{:} )
C =
3 10
6 2
6 2
10 10
10 10
10 10
  2 comentarios
dan berkowitz
dan berkowitz el 23 de Oct. de 2017
thank you!
Cedric
Cedric el 23 de Oct. de 2017
My pleasure!

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