How do you divide each row by its first nonzero element?

How you would divide each row by its first nonzero element? For example, if I have a matrix A=[1 9 7;0 2 4;0 0 5], I want it to be [1 9 7;0 1 2; 0 0 1] where the diagonals of the matrix are 1s. As you can see, I want the first row and all of its columns to be the same. Would it also be possible to have the code for this problem be 1 line?

[Stephen23]

What do you mean that you "want... all of its columns to be the same"?

[jones matthew]

I meant to say the elements of the first row of the matrix to be the same. Anyways, you answered my questions already and it works for me. Thank you!

Answer 1

[Stephen23]

>> A = [4,9,7;0,2,4;0,0,5];
>> B = bsxfun(@rdivide,A,diag(A));
>> B(1,:) = A(1,:)
B =
   4   9   7
   0   1   2
   0   0   1