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sig = 1; % Source strength % GRID: x = -150:.02:150; y = 0:.02:100; for m = 1:length(x) for n = 1:length(y) xx(m,n) = x(m); yy(m,n) = y(n); % Velocity potential function: phi_Source(m,n) = (sig/4/pi) * log(x(m)^2+(y(n)+.01)^2); % Stream function: psi_Source(m,n) = (sig/2/pi) * atan2(y(n),x(m)); end end % Plots % Source at origin of coordinat systex: contour(xx,yy,psi_Source,(-0.5:.5:5),'k') hold on contour(xx,yy,phi_Source,10,'r') legend('streamlines' ,'potential') title(' Source at origin') axis image hold off
1 comentario
Eric
el 6 de Nov. de 2017
Here is the code properly formatted (you're welcome, Ricardeo):
sig = 1;
% Source strength
% GRID:
x = -150:.02:150;
y = 0:.02:100;
for m = 1:length(x)
for n = 1:length(y)
xx(m,n) = x(m);
yy(m,n) = y(n);
% Velocity potential function:
phi_Source(m,n) = (sig/4/pi) * log(x(m)^2+(y(n)+.01)^2);
% Stream function:
psi_Source(m,n) = (sig/2/pi) * atan2(y(n),x(m));
end
end
% Plots
% Source at origin of coordinate system:
contour(xx,yy,psi_Source,(-0.5:.5:5),'k')
hold on
contour(xx,yy,phi_Source,10,'r')
legend('streamlines' ,'potential')
title(' Source at origin')
axis image
hold off
ProTip: Check out meshgrid to transform it into:
[yy xx] = meshgrid(y,x);
phi_Source = (sig/4/pi) .* log(xx.^2+(yy+0.01).^2);
psi_Source = (sig/2/pi) .* atan2(yy,xx);
and avoid for loops.
Respuestas (2)
Image Analyst
el 6 de Nov. de 2017
It runs for me. Takes like 25 minutes though. What is your question?
0 comentarios
Eric
el 6 de Nov. de 2017
Be patient, it just takes a long time to display the plots. For me it took about 2 seconds for the contour functions to return and about 86 seconds for the figure to display. You may want to look into alternative ways to plot, or ways to reduce the number of elements plotted, if you desire speed.
0 comentarios
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