Borrar filtros
Borrar filtros

Why does a'*b yield a (slightly) different result than dot(a,b)?

2 visualizaciones (últimos 30 días)
I was working an building a matrix entry-wise and checking two different methods against each other and eventually found that dot(a,b) is giving me a different answer than a'*b, where a and b are both real 9948x1 column vectors. I can see that the implementation of dot uses conj(a)*b, but my vectors are real. In one example, dot(a,b) = -1.0351e-11 and a'*b = -8.6402e-12.
I think it's likely a floating point precision issue, but I'm curious about the implementation of the "*" operator and what might be leading to it. Can anyone shed some light on this?
  3 comentarios
EQ
EQ el 28 de Nov. de 2017
I'm attaching two vectors a and b that show the issue. I'm using R2015b.
Guillaume
Guillaume el 28 de Nov. de 2017
Indeed with your inputs I get the same discrepancy in R2017b. No idea why.

Iniciar sesión para comentar.

Respuesta aceptada

Walter Roberson
Walter Roberson el 28 de Nov. de 2017
For sufficiently large arrays, a'*b is going to invoke the high performance libraries, which are going to calculate the multiplications in multiple threads, doing partial summations, before eventually doing a final summation. Because the summations could be done in a different order than sum(conj(a).*b), the round-off can be different.

Más respuestas (0)

Categorías

Más información sobre Matrices and Arrays en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by