How the increment size would affect solving an equation ?
Mostrar comentarios más antiguos
I have a function, and this function should calculate simple equation in a range from 0 to pi/2; the main issue is that I would like to have accurate results, and this require small increment. Here is the function:
function [Sg_wk]=MM(M1,delta)
Y=1.4;
Sg=0:0.001:pi/2;
Del=zeros(1,length(Sg));
for i=1:1:length(Sg)
Del(i)=atan((2*cot(Sg(i))*(M1^2*sin(Sg(i))^2-1))/( 2+M1^2*(Y+cos(2*Sg(i)))));
end
Sg_wk=interp1(rad2deg(Del), rad2deg(Sg), delta, 'linear');
end
If I run this code with >> MM(2,4) ans = 48.6861
The correct answer is 33.39024 If I use the same code with smaller increment (Sg=0:0.1:pi/2), it provides: >> MM(2,4)
ans = 33.4677
much better, but does not that contradict the logic ???
Also, Del now will be calculated, how can extract only the positive values out of the whole matrix ?
Respuesta aceptada
Más respuestas (0)
Categorías
Más información sobre Least Squares en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
