How can i find largest 8 bit number from these 08 bit numbers i m getting ?

a=imread('C:\Users\a.png');
disp(a);
for i=1:256
  for j=1:256
    b(i,j,1) = de2bi(a(i,j),8);
    disp(b)
  end
end

Answer 1

[dpb]

That's a new one to me...but, it's not of a lot of use for the purpose you're asking about as it is still a vector representation of the binary value albeit numeric rather than character as does dec2bin. You still can't do comparisons or arithmetic or the like on the results other than on an element-by-element (bit-by-bit) basis.

To find the maximum or anything else numeric other than bit-wise operations on the elements as bit values, simply use the original array--

[maxa,idxmax]=max(a(:));   % find max, location of max overall in array

NB: the (:) to address the array a as a vector; the location will be the linear position in the array. If you need the location in the array itself, then

[imx,jmx]=ind2sub(size(a),idmax);

[diwa]

If there is no such matrix & I just have to compare between two or three 8bit numbers to find the largest one ?

[diwa]

It is showing error , undefined function 'max' for input arguments of type 'cell'.

[dpb]

To reference cell content use the "curlies", ie, {} instead of (). See doc on cell and cell arrays for how to reference cell contents.

[maxa,idxmax]=max(a{:});

[dpb]

"compare between two or three 8bit numbers..."

Then construct an array dynamically...

[maxa,idxmax]=max([a,b,c]);

[diwa]

Thank you so much