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How to call and also return a matrix in a function?

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Khushank Singhal
Khushank Singhal el 10 de Dic. de 2017
Respondida: KL el 11 de Dic. de 2017
I have a certain requirement in my code that I need to define a separate function for computation of a variable. The variable is a matrix of order of 32x32. As inputs to the function, there are two different matrices of the same order. After calling the function in the code, I want the function to return the whole matrix of order 32x32.
This is how I am writing it currently (but it is not correct):
-calling the function :
matrix = variable(input1, input2);
where 'matrix' is the output and 'variable' is the function name. 'input1' and 'input2' are also matrices of order 32x32.
-function:
function output = variable(in1, in2)
I wanted to know the correct method to do this.
The error that I am getting:
Output argument "output" (and maybe others) not assigned during call to "variable".
Error in test (line 108)
matrix = variable(input1, input2);
  3 comentarios
Matt J
Matt J el 10 de Dic. de 2017
Editada: Matt J el 10 de Dic. de 2017
There is no error in what you have shown so far, but you haven't shown very much. What is the body of the function variable() doing and what is the error message?
Stephen23
Stephen23 el 11 de Dic. de 2017
"This is how I am writing it currently (but it is not correct)"
"I wanted to know the correct method to do this."
What you have shown us is correct. If you are getting any error message then please show us the complete error message (this means all of the red text).

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Respuesta aceptada

KL
KL el 11 de Dic. de 2017
Output argument "output" (and maybe others) not assigned during call to "variable"
Just as it says you probably haven't assigned anything to output. For example, if you want to add in1 and in2 to form output, it should be,
function output = variable(in1,in2)
output = in1+in2;
end
Passing a matrix is just like passing any other variables into a function but just that you have to know their sizes to do any computations on it. Here I assumed both are same size and so the output will be of their size as well.

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