How to change the axis location for multiple subplots ?
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I try to change the axis location for 2 subplots
when I entered this code
n = [-5:5];
x = 2*impseq(-2,-5,5) - impseq(4,-5,5);
subplot(2,2,1);
stem(n,x);
ax=gca;
ax.XAxisLocation = 'origin';
ax.YAxisLocation = 'origin';
title('Sequence in Problem 2.1a');
xlabel('n'); ylabel('x(n)');
ax.Box = 'off';
ax.Layer = 'top';
n = [0:20];
x1 = n.*(stepseq(0,0,20)-stepseq(10,0,20));
x2 = 10*exp(-0.3*(n-10)).*(stepseq(10,0,20)-stepseq(20,0,20));
x = x1+x2;
subplot(2,2,3);
stem(n,x);
ax.XAxisLocation = 'origin';
ax.YAxisLocation = 'origin';
title('Sequence in Problem 2.1b');
xlabel('n'); ylabel('x(n)');
It changes it for the first subplot only ..why is this?
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Respuestas (2)
Jan
el 14 de Dic. de 2017
Editada: Jan
el 14 de Dic. de 2017
Because your
ax.XAxisLocation = 'origin';
ax.YAxisLocation = 'origin';
concerns the same object "ax". Try this:
ax2 = subplot(2,2,3);
stem(n,x);
ax2.XAxisLocation = 'origin';
ax2.YAxisLocation = 'origin';
Note that
ax = subplot(2,2,1);
is safer than;
subplot(2,2,1);
stem(n,x);
ax=gca;
If the user clicks around in the GUI during stem works, the current axes replied by gca is changed. Better catch the handles directly from the function, which creates the objects instead of searching them afterwards by gca or gcf.
5 comentarios
Jan
el 17 de Dic. de 2017
@omar khater: While "I want the subplot 2,3 to be as 1" is clear to you, the readers have to guess, what this means. Remember that I do not have the faintest idea about what you want.
As you see in the attached image, I want...
The image shows, what you get, but not what you want instead.
The posted code does exactly, what is expected. The locations of the axes are moved to the corresponding origins - this is on the left for the upper right axes, and on the left bottom corner for the lower axes. So please explain exactly what does not appear as you want.
Yoseph
el 6 de Oct. de 2022
n = [-5:5];
x = 2*impseq(-2,-5,5)-impseq(4,-5,5);
stem(n,x); title('Sequence in Problem 2.1a')
xlabel('n'); ylabel('(n)');
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