Why ParFor does not work for this?

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Erdem Uguz
Erdem Uguz on 27 Dec 2017
Answered: Namnendra on 19 Jun 2022
It is a really simple manipulation. I want to replace some lines of the matrix with zeros.
A=rand(20,20);
for j=1:1:4
A(4*j+1,:)=zeros;
end
When I replace for with parfor I get a classification error. But the results of the manipulation is independent from each other. I don't understand why.
Thank you Erdem

Answers (1)

Namnendra
Namnendra on 19 Jun 2022
All variables referenced at the top level of the parfor must be resolved and classified. Go through the following link to know more :-
You can try putting the body of perfor loop into a function and calling the function from the loop.
I hope this helps.

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