Manipulating arrays within a cell array

10 visualizaciones (últimos 30 días)
mathman
mathman el 4 de En. de 2018
Editada: mathman el 7 de En. de 2018
I have a cell array, A_C which has 401 cells (1x401) each with arrays of varying sizes, but same dimensionality. I'm trying to divide each element within an array by the number of elements within that array. And then replace the array with the new one.
So for example, the array A(1,2) = 1x101, I want to divide each element within this array by 101, B = A(1,2)/101 and then I want to replace the array at A(1,2) by B.
  1 comentario
mathman
mathman el 4 de En. de 2018
I think I solved it, I'll leave the thread up incase someone wants to do something similar.

Iniciar sesión para comentar.

Respuesta aceptada

Jan
Jan el 4 de En. de 2018
Editada: Jan el 4 de En. de 2018
% Create some test data: (your code)
dxs = 0:5e-06:0.002;
nCell = length(dxs);
xs = cell(1, nCell); % Pre-allocate!!!
for k = 1:nCell
xs{k} = 0:dxs(k):5e-04;
end
% Divide each cell by its length:
B = cell(size(xs)); % Pre-allocate!!!
for k = 1:nCell
B{k} = xs{k} / length(xs{k});
end
Simple with a loop, isn't it? I find "nCell" nicer than "num_cells_dxs" and avoid "l" as variable, because it is confused with 1 easily.
I assume the cellfun is nicer, but slower:
B = cellfun(@(c) c / length(c), xs, 'UniformOutput', false)

Más respuestas (1)

mathman
mathman el 4 de En. de 2018
for n = 1:l
xs_current1{n} = xs_current1{1,n}/num_point_sources(1,n);
end

Categorías

Más información sobre Resizing and Reshaping Matrices en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by