In the following code I get matrix 'a' with repeated columns. How to generate it without repetition?

if true
k=3; 
n=5;
m=(2*k)-2;
n1=k-1;
N=(factorial(m))/(factorial(n1)*factorial(n1));
o = ones(k-1,1) ;
z = zeros(k-1,1) ;
a1 = [o ; z];
n2=1;
for i=1:N
a(:,n2)= randsample([o ; z],m)
n2=n2+1;
end 
end

Answer 1

[KSSV]

k=3;
n=5;
m=(2*k)-2;
n1=k-1;
N=(factorial(m))/(factorial(n1)*factorial(n1));
o = ones(k-1,1) ;
z = zeros(k-1,1) ;
a1 = [o ; z];
v = a1' ;
C = unique(perms(v),'rows') ;

[PLACEIUS NISHIGA G]

Thank you sir. It helped us. But the elements in each column is the same every time I execute it. The elements in each column need to be randomly generated for every execution without repetition with other columns.

if true
  % code
k=3;
n=5;
m=(2*k)-2;
n1=k-1;
N=(factorial(m))/(factorial(n1)*factorial(n1));
o = ones(k-1,1) ;
z = zeros(k-1,1) ;
a1 = [o ; z];
v = a1' ;
C = unique(perms(v),'rows') ;
C=C'

end