I want to understand the meaning(Syntax) of this line. Someone please explaiin what conditions are being used and what does it exactly mean in terms of variables used
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Sagar Saxena
el 22 de En. de 2018
Comentada: Sagar Saxena
el 22 de En. de 2018
Kf(fmag<=1) = ((1-(nimage*magnification*fth(fmag<=1)).^2)
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James Tursa
el 22 de En. de 2018
Editada: James Tursa
el 22 de En. de 2018
The result of fmag<=1 is a logical variable. The expression fth(fmag<=1) picks of those elements of fth that are at the locations of the "1" elements of the logical indexing. I.e., it picks off the fth values at the locations where fmag<=1 is true. The remaining expression on the rhs of your assignment is then evaluated for those elements, and the results are stored in the same locations (using the same logical indexing) of the Kf variable. E.g.,
>> fth = 1:10
fth =
1 2 3 4 5 6 7 8 9 10
>> Kf = zeros(size(fth))
Kf =
0 0 0 0 0 0 0 0 0 0
>> fmag = 2*rand(1,10)
fmag =
1.4121 0.0637 0.5538 0.0923 0.1943 1.6469 1.3897 0.6342 1.9004 0.0689
>> fmag<=1
ans =
1×10 logical array
0 1 1 1 1 0 0 1 0 1
>> Kf(fmag<=1) = fth(fmag<=1)
Kf =
0 2 3 4 5 0 0 8 0 10
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