Extract a range of data acording to the date range from a table
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Mark Rodger
el 1 de Feb. de 2018
Comentada: Guillaume
el 7 de Feb. de 2018
I want to separate months of the year from a table into another table for each season.
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Peter Perkins
el 1 de Feb. de 2018
There's only four seasons, best to not overthink this.
spring = t(ismember(month(t.Time),1:3),:);
etc. But Guillaume's advice is worth thinking about.
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Fraser McMurray
el 7 de Feb. de 2018
Editada: Fraser McMurray
el 7 de Feb. de 2018
If you want to view a specific year you can try this:
april = x(ismember(month(x.time),4),:);
april2013 = april(ismember(year(april.time),2013),:);
Guillaume
el 7 de Feb. de 2018
Again, it is very likely that you don't need to separate the table at all and that it may be more efficient to work on the whole table at once.
For example, if you wanted to calculate the mean wind speed per season per year:
[group, season, year] = findgroups(discretize(month(yourtable.time), [1 4 10 12]), year(yourtable.time));
meanwindspeed = splitapply(@mean, yourtable.windspeed, group);
result = table(season, year, meanwindspeed)
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