Needing help with Newton Raphson method

4 visualizaciones (últimos 30 días)
bhador
bhador el 8 de Feb. de 2018
Comentada: Roger Stafford el 22 de Feb. de 2018
So, I have attached my Newton Raphson script and I just want someone to double check if it is right or not. You might not see a f or fprime because they are in a different script. I'm required to make the output x1 an array that stores each new guess as it is generated and I'm having a hard time with that.
function [x1,err,iter] = newtonraphson(f,fprime,x0,tol,max_iter)
iter = 0; while (1)
xl = x0;
x0 = xl - f(x0)/fprime(x0);
iter = iter + 1;
if x0 ~= 0
err = abs((x0 - xl)/x0);
end
if err <= tol || iter >= max_iter
break
end
end
And then below is the driver that should use the function was created above and so display the calculated values of x1 and err for each iteration in a table formatted with fprintf. Finally, make a 1 x 3 subplot clearly showing the root-finding function and the results of each iteration. I tried everything in mind but nothing worked.
y = @(x) tanh(x.^2-9) - 3;
dy = @(x) (4.*x)./(cos(18+2.*x.^2)+1); [x1,err,iter] = newtonraphson(y,dy,3.2,0.0001,3);
Note: both scripts are written separately in two different m files. Thank you in advance
  1 comentario
Roger Stafford
Roger Stafford el 22 de Feb. de 2018
Your derivative of tanh(x.^2-9) is incorrect. It should be:
dy = 2*x.*sech(x.^2-9).^2 = 2*x./cosh(x.^2-9).^2

Iniciar sesión para comentar.

Respuestas (1)

Prajit T R
Prajit T R el 22 de Feb. de 2018
Hi You can try this code:
function [xlist,err,iter] = newtonraphson(f,fprime,x0,tol,max_iter)
xlist=[x0];
iter = 0;
x1=x0;
while (1)
x0 = x1; %For the first iteration, it takes the value x0. For all later iterations, it takes the previous value.
x1 = x0 - f(x0)/fprime(x0); %As per formula
xlist(end+1)=x1; %Append the guessed value to the list
iter = iter + 1;
if x0 ~= 0
err = abs((x0 - xl)/x0);
end
if err <= tol || iter >= max_iter
break
end
end
end
Cheers

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by