Reversing an polynomial equation y = f(x) to x = f(y)

94 visualizaciones (últimos 30 días)
Hazem Elgabra
Hazem Elgabra el 13 de Mayo de 2012
Editada: John D'Errico el 19 de Feb. de 2023
I'm trying to reverse a 3rd order equation using matlab, ie: y = x^3 + x^2 + x^1 + 5 to x = f(y) I just don't know if there's an already built it function in matlab for such a task.
Thank you...
  2 comentarios
Khalid Alshumayri
Khalid Alshumayri el 19 de Feb. de 2023
Did you find anything ?
John D'Errico
John D'Errico el 19 de Feb. de 2023
Editada: John D'Errico el 19 de Feb. de 2023
@Khalid Alshumayri - did you understand the answers? This is mathematically impossible in general, certainly for polynomials of higher degree than 4. Even for lower polynomials, at best you would need to use a root finder, something like solve. There will be no single valued function you can formulate as the inverse function for most polynomials. And even if the inverse does technically exist if the polynomial is monotonic, the solution is still rather a messy one, even for 3rd or degree polynomials, involving radicals and complex numbers. Note that even degree polynomials will NEVER be monontonic functions.

Iniciar sesión para comentar.

Respuestas (2)

Walter Roberson
Walter Roberson el 13 de Mayo de 2012
polynomials of degree 2 or higher cannot be inverted to give a polynomial.
The inverse of the particular polynomial you indicate is the union of three expressions.
If you have the symbolic toolbox, you can use solve()

Marcin Konowalczyk
Marcin Konowalczyk el 1 de Nov. de 2017
@Walter is right, but what you can do is approximate them using, for example, this function. This works only in a small domain where your polynomial is well conditioned (monotonically increasing) and fails horribly otherwise, but for certain cases (see the docstring of the linked function) it is useful.

Categorías

Más información sobre Polynomials en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by