Why does the second example fail?

here's my code and the response
testvec = [Xc,Yc,sig,A]
ErrTest1 = RMS_Err_func(Image,Xc,Yc,sig,A)
ErrTest2 = RMS_Err_func(Image,testvec)
gives:
ErrTest1 =
0.0942
Not enough input arguments.
Error in NM_2D_Gauss_fit>RMS_Err_func (line 60)
r(l,m) = sqrt((l-Xc).^2+(m-Yc).^2);
Error in NM_2D_Gauss_fit (line 46)
ErrTest2 = RMS_Err_func(Image,testvec)

3 comentarios

Walter Roberson
Walter Roberson el 13 de Feb. de 2018
NM_2D_Gauss_fit and RMS_Err_func appear to be your own code.
In your first call you are passing in four inputs to RMS_Err_func. In the second call you are only passing in two inputs. We can only guess that RMS_Err_func needs more than 2 inputs.
Derrick Salmon
Derrick Salmon el 13 de Feb. de 2018
Walter
Is there no way for the function so see the contents of testvec?
Walter Roberson
Walter Roberson el 13 de Feb. de 2018
... Yes?
You are passing it in to the function, so the second argument can examine the contents of testvec.

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 Respuesta aceptada

Walter Roberson
Walter Roberson el 13 de Feb. de 2018
I suspect that your testvec is a vector that has within it values for Xc, Yc, sig, A . If so then,
temp = num2cell(testvec);
ErrTest2 = RMS_Err_funct(Image, temp{:});

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