Add row and column to a interdependent matrix

Hi, how to change the below mentioned 'A' matrix to 'AA' matrix by adding a row and column of 'CR' with the exact values for 'CR' as mention below. For 'CR' all the values in the row from CR to E221 will have 0 and in the column, CR will be zero and E1 to E221 will be 1. I want that string 'CR' also need to be added to the existing headings of E1 to E221 in the row and column wise.

Answer 1

[KSSV]

A = rand(10) ;
AA = zeros(size(A)+1) ;
AA(2:end,2:end) = A ;
AA(2:end,1) = 1 ;

[Santhosh Chandrasekar]

Can you please tell me how to add it to this code. I want that column name and row name 'CR' also to be added to the final matrix along with the values.

 nm= cellstr(reshape((string({'E','R','E','S','E','E','E','E','E','E','E','E','E','E','E','E','E','E','E','E','E','E','E','E','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR','SR',}) + ([101,1,106,1,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20] + (0:4)'))',[],1))
N = zeros(44);
N(2:end,1)= 1
N(3:end,2)= 1
N(4,3)= 1
N(5:end,4)= 1
N(25,5)= 1;N(26,6)= 1;N(27,7)= 1;N(28,8)= 1;N(29,9)= 1;N(30,10)= 1;N(31,11)= 1;N(32,12)= 1;N(33,13)= 1;N(34,14)= 1;N(35,15)= 1;N(36,16)= 1;N(37,17)= 1;N(38,18)= 1;N(39,19)= 1;N(40,20)= 1;N(41,21)= 1;N(42,22)= 1;N(43,23)= 1;N(44,24)= 1;
N1=N;
T= repmat({N1},1,5)
A= [{nan},nm';nm,num2cell(blkdiag(T{:}))]