How do I plot a point at the x intercept on this graph?
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e=1;
sigma=0.154;
r=linspace(0.154,1,100);
U = @(e,sigma,r) 4*e*((sigma./r).^12)-((sigma./r).^6);
norm_r = r./sigma;
figure
plot(norm_r,U(e,sigma,r))
title('Lennard-Jones Potential')
xlabel('Distance (nm)')
ylabel('Potential Energy')
2 comentarios
dpb
el 20 de Feb. de 2018
Not sure precisely what you want to add where???
Rhianne Tallarico
el 20 de Feb. de 2018
Respuestas (1)
Are Mjaavatten
el 20 de Feb. de 2018
Let U be a function of r only and find the solution to U(r) = 0:
e=1;
sigma=0.154;
r=linspace(0.154,1,100);
U = @(r) 4*e*((sigma./r).^12)-((sigma./r).^6);
norm_r = r./sigma;
figure
plot(norm_r,U(r))
title('Lennard-Jones Potential')
xlabel('Distance (nm)')
ylabel('Potential Energy')
norm_r_0 = fzero(U,1)/sigma;
hold on; plot(norm_r_0,0,'*r')
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