Entire Column Disappears After Sorting

1 visualización (últimos 30 días)
Mark Tenorio
Mark Tenorio el 10 de Mzo. de 2018
Respondida: Mark Tenorio el 10 de Mzo. de 2018
I'm trying to sort a column based on some indexing. I tried to copy the way it was done here https://stackoverflow.com/questions/16072984/sorting-cell-array-based-on-column-double-not-char-values but for a larger cell array.
I attached my code. My code will work for textfile1 but not textfile2 because of dimension mismatch. See attached for both text files. Pretend that the input (textfile1 and textfile2) are of class cell.
This is line 32:
number_Holder2 = number_Holder2(index_Ratings);
where the size of number_Holder2 is 5x1 after being run. However, before this line of code is run, the cell is 5x2 ... which I want it to be because when line 39 is run:
sorted_DoubleArray = [list(1,2:end);number_Holder2Complete]; %concatnate
I get a dimension error in my code.
Is there a way that I can adjust line 32 so that it wont remove a column?
Edit: Not allowed to use sortrows() unfortunately.
  4 comentarios
Stephen23
Stephen23 el 10 de Mzo. de 2018
Editada: Stephen23 el 10 de Mzo. de 2018
@Mark Tenorio: the link I gave you is not for sortrows. I should know, I wrote it!
Mark Tenorio
Mark Tenorio el 10 de Mzo. de 2018
Not sure if your link does it but I found a way. Just use a for loop to iterate through each column and index like that instead of trying to do it in one line of code.

Iniciar sesión para comentar.

Respuesta aceptada

Mark Tenorio
Mark Tenorio el 10 de Mzo. de 2018
Not sure if your link does it but I found a way. Just use a for loop to iterate through each column and index like that instead of trying to do it in one line of code.

Más respuestas (0)

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by