Borrar filtros
Borrar filtros

Draw rectangular contour in thresholded image

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Nachiket Patki
Nachiket Patki el 20 de Mzo. de 2018
Comentada: Nachiket Patki el 4 de Abr. de 2018
Hello, I have a thresholded image of a bottle, where the liquid color is being masked and thresholded.
Now I want to find the height of that liquid present inside the bottle. What I am thinking is I will find the rectangular contour covering the liquid inside the bottle...and the height of the rectangle will give me a height of liquid. So how to draw react contour is the first question or is there any better way of finding height of liquid present?
Thank you

Respuestas (1)

Image Analyst
Image Analyst el 20 de Mzo. de 2018
What you are saying is this:
binaryImage = bwareafilt(binaryImage, 1); % Extract largest blob only.
props = regionprops(binaryImage, 'BoundingBox');
height = props.BoundingBox(4)
This way is susceptible to little outliers, like the two you have on the top. A better way may be to either scan the blob vertically getting the height at every column and then taking the average
heights = zeros(rows, 1);
for col = 1 : columns
thisColumn = binaryImage(:, col);
if max(thisColumn) > 0 % If there are white pixels in the column
topRow = find(thisColumn, 1, 'first');
bottomRow = find(thisColumn, 1, 'last');
heights(col) = bottomRow - topRow + 1;
end
end
averageHeight = mean(heights(heights>0))
Or, get the average vertical profile and threshold it at some level
verticalProfile = sum(binaryImage, 2);
averageHeight = sum(verticalProfile > someLevel)
All 3 methods will/could give different heights. It just depends on how you want to define height. I mean, look at the bottom of your bottle - it's not flat so you don't have a perfect rectangle aligned with the edges of the image, so there are different ways to define height.
  7 comentarios
Image Analyst
Image Analyst el 25 de Mzo. de 2018
Editada: Image Analyst el 25 de Mzo. de 2018
If you're going to write out four strings, you'll need four %s in the format specifier string.
n = handles.edit1.String;
r = handles.edit2.String;
b = handles.edit3.String;
y = handles.edit4.String;
outputFileID = fopen(fullOutputFileName, 'wt');
fprintf(outputFileID, '%s %s %s %s %s\n', n, r, b, y);
fclose(outputFileID);
Nachiket Patki
Nachiket Patki el 4 de Abr. de 2018
Ohh I just missed that... Again thank you very much, sir. Your answers have always helped me.

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