reading an array
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Hello All, I Have code below. I want to create an array with elements [ 5, 10, 15, 20,25, 30, 35, 40, 45, 50, 55, 60, 65, 75, 80, 85, 90, 95, 100] and I want replace if statement if (stateCount(n)> 5 && stateCount(n)<= 10) with value from an array 5 and 10. How can I do that. Any tips will gladly welcome
stateHit = zeros(length(stateCount),20);
for n = 1:length(stateCount)
if (stateCount(n)<= 5)
stateHit(n,1) = 1;
else
if (stateCount(n)> 5 && stateCount(n)<= 10)
stateHit(n,2) = 1;
else
if (stateCount(n)>10 && stateCount(n)<= 15)
stateHit(n,3) = 1;
else
if (stateCount(n)> 15 && stateCount(n)<= 20)
stateHit(n,4) = 1;
else
if (stateCount(n)> 20 && stateCount(n)<= 25)
stateHit(n,5) = 1;
else
if (stateCount(n)> 25 && stateCount(n)<= 30)
stateHit(n,6) = 1;
end
end
end
end
end
end
end
Many thanks in advance
SM
0 comentarios
Respuestas (4)
Walter Roberson
el 25 de Mayo de 2012
YourDividingArray = 5:5:100;
[bincounts, HistcIndex] = histc(StateCount, [-inf YourDividingArray(2:end)]);
StateHit( sub2ind(size(StateHit), HistcIndex, 1:size(StateHit,2)) ) = 1;
Or if you prefer,
HistcIndex = max(1, floor(StateCount / 5));
StateHit( sub2ind(size(StateHit), HistcIndex, 1:size(StateHit,2)) ) = 1;
0 comentarios
Sayanta
el 25 de Mayo de 2012
1 comentario
Walter Roberson
el 25 de Mayo de 2012
Typo on my part. My StateHit should be stateHit to be consistent with your code. I assume here your line
stateHit = zeros(length(stateCount),20);
Patel Keyur
el 7 de En. de 2022
How to read array in matlab and this array value store in any number device?
0 comentarios
Ver también
Categorías
Más información sobre Multidimensional Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!