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speed up the & operation

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Chaoyang Jiang
Chaoyang Jiang el 12 de Abr. de 2018
Comentada: Walter Roberson el 13 de Abr. de 2018
How to speed up the following code? I did profiling, and this line takes 3267.72s for calling 245913489 times.
a=[1 0 1 1 0 1 1 1 1 1 0 0 1 1 0 1 1 1 0 1 1 0 1 1 1 0 1 1 0 1 1 1];
b=[1 0 1 1 0 1 1 1 1 1 0 0 1 1 0 1 1 1 0 1 1 0 1 1 1 0 1 1 0 1 1 1 1 1 1 1 1 0 0 1 1 0 1 1 1 0 1 1 0 1 1 1 0];
for i=1:1000000
aat=((a(1,1:24)==0)&(b(1,25:48)==1)&(~ismembc(1:24,5:50)))';
end
  5 comentarios
Chaoyang Jiang
Chaoyang Jiang el 13 de Abr. de 2018
ismembc seems to be faster than ismember, that is why I used this function.
Walter Roberson
Walter Roberson el 13 de Abr. de 2018
for i=1:1000000
part1 = a(1,1:24)==0;
part2 = b(1,25:48)==1;
part3 = ~ismembc(1:24,5:50);
part4 = part1 & part2 & part3;
aat = part4 .';
end
Now when you profile you can see exactly which part of the expression is taking the most time.
We suspect that it is the ismembc() that is taking all of the time and that the & is relatively fast.

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