How to flip values greater than zero in a row

If I have a row in matrix like that

0 0 0 0 1 2 3 0 0 0

I want to make it like that

0 0 0 0 0 0 3 2 1 0

If it is possible to do?

[Stephen23]

@Tanmoyee Bhattacharya: the numbers a not only flipped L-R, but have been translated too. How is the new position determined?

Answer 1

[Birdman]

Try this:

A=[0 0 0 0 1 2 3 0 0 0]
idx=find(A~=0);
A(idx+nnz(A)-1)=fliplr(A(idx));
A(idx(1:end-1))=0

[Tanmoyee Bhattacharya]

Thank you so much sir.It is very much useful. It is working for one row perfectly.I have multiple rows Two are

A=[0  0  0  0  0  0.105037027  0.894962973  0  0  0
;0  0  0  0  0  0  0.990679262  0.009320738  0  0
];

It should be like

0

  0  0  0  0  0  0.894962973  0.105037027  0  0

0  0  0  0  0  0  0  0.009320738  0.990679262  0

But the result is coming

0  0  0  0  0  0  0  0  0.990679262000000  0.00932073800000000

0  0  0  0  0  0  0  0.894962973000000  0  0

For many rows how to change the code?