Changing the value in the popupmenu
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Quan Seah
el 23 de Abr. de 2018
Comentada: Quan Seah
el 23 de Abr. de 2018
The first item of my popupmenu is an instruction so it really isn't a value, but MATLAB seems to take it as a value whenever i accidentally pick it. Let's say I want to assign "5" to my second item, how do I make it show 5 instead of 2 because whenever I do the calculation MATLAB uses 2 instead of 5.
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Walter Roberson
el 23 de Abr. de 2018
lookup_table = [nan, 5, 10, -4, 18];
idx = get(hObject, 'value');
if isempty(idx)
... user has not chosen anything
elseif idx > length(lookup_table)
... mismatch between lookup table and number of entries in String property
else
associated_value = lookup_table(idx);
if isnan(associated_value)
... opps, user chose a header.
end
end
3 comentarios
Walter Roberson
el 23 de Abr. de 2018
popChoice = contents{get(hObject,'Value')}; [tf, idx] = ismember(popChoice, {'Black', 'Brown', 'Red', 'Orange', 'Yellow', 'Green', 'Blue', 'Violet', 'Grey', 'White'}); if ~tf ... user choose a header or has not made any choice else popVal = 10 * (idx-1); end
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