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big M constraints bringing an infeasinle solution

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Paramvir Singh
Paramvir Singh el 5 de Mayo de 2018
Comentada: Nicola Blasuttigh el 17 de En. de 2021
Here Tins is a decision variable of size=(24,1) in my optimization problem. The value of Tins(min_des) =20 while value of Tins(max_des) = 23.
I have tried using the following constraints for the above equation in MILP problem.
(Tmin - Tins) - M1*(1-BCac) <= 0 where M1 is an upper bound on (Tmin - Tins)
(Tins - Tmax) - M2*BCac <= 0 where M2 is an upper bound on (Tins - Tmax)
But if its supposed that Tins=27
then my first constraint gets satisfied with both BCac=1 and BCac=0
although the second constraint is satisfied at BCac=1 only, which is correct.
But due to the first constraint, my program is getting an infeasible solution.
Any help would be deeply appreciated.
  5 comentarios
Paramvir Singh
Paramvir Singh el 6 de Mayo de 2018
Sorry, the code is running in my software. But the result is no feasible solution. Here, check it out in the pic below:
Mary Fenelon
Mary Fenelon el 9 de Mayo de 2018
Paramvir is using the new syntax for specifying solve options introduced in 18a.
Paramvir, here a couple of suggestions to diagnose the infeasibility:
  • Write a text version of the problem with writeproblem and make sure your constraints are as you expect
  • Often, it's one group of constraints that lead to infeasibility. Try to identify that group by commenting out groups of constraints.

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Paramvir Singh
Paramvir Singh el 10 de Mayo de 2018
Thanks a lot Mam, I too figured it out that solve options is introduced recently in the 2018a version of Matlab. I was giving out of bounds initial value to the Tins variable. Moreover, one of the big M constraint in my main program was given a wrong form. Also there were two equality constraints of Tins variable(both containing its formula for cooling and heating version), I edited that formula and now my program is giving satisfactory results.
Thanks a lot to Matt J for helping me out.

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