Fitting a plane through a 3D point data

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ha ha
ha ha el 6 de Mayo de 2018
Editada: Matt J el 6 de Mayo de 2018
For example, i have 3d point cloud data [xi, yi, zi] as the attachment .txt file. I want to fit a plane to a set of 3D point data. What kind of method to do that?
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Matt J
Matt J el 6 de Mayo de 2018
How does one know that M and L are different planes and not just noise? Is there a known upper bound on the noise? A known lower bound on the separation distance between M and L?

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Matt J
Matt J el 6 de Mayo de 2018
You will probably have to implement a RANSAC plane fitting routine.
  5 comentarios
ha ha
ha ha el 6 de Mayo de 2018
Thanks.
Matt J
Matt J el 6 de Mayo de 2018
Editada: Matt J el 6 de Mayo de 2018
One approach you might consider is to take planar cross sections of your data. This will give 2D data for a line, with outliers. Then you can apply a ready-made RANSAC line-fitter, like the one I linked you to. From line fits in two or more cross-secting planes you should be able to construct the desired plane K.

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Más respuestas (2)

Walter Roberson
Walter Roberson el 6 de Mayo de 2018
data = load('1.txt');
coeffs = [data(:,1:2), ones(size(data,1),1)]\data(:,3);
The equation of the plane is then coeffs(1)*x + coeffs(2)*y - coeffs(3) = z
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ha ha
ha ha el 6 de Mayo de 2018
Editada: ha ha el 6 de Mayo de 2018
From your answer, I plot the surface as below image. But That plane is not same as my expected plane. If we use the formulas as your proposed method, the plane is fitting through all points & will be slightly different with my expected plane K(=plane M)

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Matt J
Matt J el 6 de Mayo de 2018
Editada: Matt J el 6 de Mayo de 2018
xyz=load('1.txt');
xyz(xyz(:,2)>40, :)=[];
mu=mean(xyz,1);
[~,~,V]=svd(xyz-mu,0);
normal=V(:,end).';
d=normal*mu';
The equation of the plane is then xyz*normal.' = d
  3 comentarios
ha ha
ha ha el 6 de Mayo de 2018
In my question: Plane M contains a large number of point data when compared with plane L(i.e., 90%). I wanna find the plane can cover large number points as plane M. Example: in the general, there are some outlier(or noise) points. So, the result will be affected significantly. Because you are using "least square regression method" as I guessed
Matt J
Matt J el 6 de Mayo de 2018
How does one know that M and L are different planes and not just noise? Is there a known upper bound on the noise? A known lower bound on the separation distance between M and L?

Iniciar sesión para comentar.

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