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Editing cell array values (each cell is a matrix)

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Ahsan  Khan
Ahsan  Khan el 10 de Mayo de 2018
Comentada: Ameer Hamza el 12 de Mayo de 2018
M=[];
M=dlmread('data.txt', '\t');
dataArray=M;
C= corrcoef(M(:,1:end));
imagesc(C);
cb = colorbar;
ylabel(cb, 'Correlation Coefficient');
moo=sqrt(C^.2)
moos=[]
for l=0:.1:1;
moo(moo<l)=0;
moos{end+1} = moo;
moos(moos>0)=1;
The last opertaion fails since > is an undefined operator for input arguments like cell. I unsuccessfully tried to make a function for the last line and implement it in cellfun. What would be the proper syntax here?
  2 comentarios
Stephen23
Stephen23 el 11 de Mayo de 2018
Editada: Stephen23 el 11 de Mayo de 2018
@Ahsan Khan: what is your question?
Ahsan  Khan
Ahsan  Khan el 11 de Mayo de 2018
Editada: Ahsan  Khan el 11 de Mayo de 2018
Well I figured out what I needed but now I'm trying to work out my next step, updated the question

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Ameer Hamza
Ameer Hamza el 12 de Mayo de 2018
"The last operation fails since > is an undefined operator for input arguments like the cell."
You cannot directly perform the comparison on cell array. you need to access its element using curly brackets and then operate on them. For example, the following syntax will work
moos{end}(moos{end}>0) = 1;
to apply this operation to all elements of moos use cellfun as following
moos = cellfun(@(x) x.*(x<0)+(x>0)*1, moos, 'UniformOutput', 0)
  2 comentarios
Ahsan  Khan
Ahsan  Khan el 12 de Mayo de 2018
I see, I saw the second format on another forum page, can you explain the @(x) x.*(x<0)+(x>0)*1 piece. For all entries if x<0 or x>0 set equal to 0?
Ameer Hamza
Ameer Hamza el 12 de Mayo de 2018
x.*(x<0)+(x>0)*1 means that if entries are less than 0 than don't change them but if they are greater then 0, then make them 1. This is what I thought you are trying to do from your line
moos(moos>0)=1;

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possibility
possibility el 11 de Mayo de 2018
before starting the iteration,
mos=[];
"before starting the removal of the next mo", most probably inside-end of the iteration,
mos{l*10}=mo;
  1 comentario
Ahsan  Khan
Ahsan  Khan el 11 de Mayo de 2018
Editada: Ahsan  Khan el 11 de Mayo de 2018
This adds the entry only to the last space of mos{} All other entries are empty,
Update: Got it working with the following code.
moos=[]
...
for l=0:.1:1;
moo(moo<l)=0;
moos{end+1} = moo;
end;
...

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