How can I find the area above the parabolic curve for this particular case?

Hi, I am new to MATLAB (so pardon me for a rather elementary question). I need to find the area above the curve (z=0.0012*v^1.5) by integration as shown in the figure.

I tried using this:

Area = sum(v(v>0))

I am not sure if this is giving me the area correctly. What else can I try using Matlab?

Answer 1

[sloppydisk]

An elegant way to do this is via function handles:

x = linspace(0, 11, 100);
y = @(x) .0012*x.^1.5;

yforArea = @(q) max(y(x)) - y(q);
area = integral(yforArea, 0, max(x))

Or just via trapezoidal integration directly:

x = linspace(0, 11, 100);
y = .0012*x.^1.5;

z = trapz(x, max(y)-y)