Borrar filtros
Borrar filtros

loop in a column to calculate max and min in a certain interval

2 visualizaciones (últimos 30 días)
sud
sud el 28 de Mayo de 2018
Comentada: jonas el 28 de Mayo de 2018
i have a column that has 200 values of length for each volume. and there can be n no. of volumes. so i need to calculate the maximum and minimum of lengths for each volume and plot volume(vs)minlength and volume(vs)maxlength in the same plot. please suggest a loop and how to apply it. help is much appreciated.
  2 comentarios
jonas
jonas el 28 de Mayo de 2018
What do you mean by volume? Can you provide an example? The problem is not clear to me.
Stephen23
Stephen23 el 28 de Mayo de 2018
Editada: Stephen23 el 28 de Mayo de 2018
sud's "Answer" moved here:
hi! i will attach a file. so its 1st column is volume and 16th column is length.

Iniciar sesión para comentar.

Respuestas (2)

KSSV
KSSV el 28 de Mayo de 2018
Let V be your volume and A be other column.
[c,ia,ib] = unique(V) ;
N = length(c) ;
iwant = zeros(N,1) ;
for i = 1:length(c)
iwant(i) = mean(A(ib==i)) ;
end
  1 comentario
sud
sud el 28 de Mayo de 2018
Hi. It is working. thanks but maybe i didnt put my problem correctly. I want to apply a loop for thia program written below! (after every 200 lengths):
IdlCatalogue_Dir='C:\Users\yadav\Desktop\IDL_routine\OUTPUT_FILE\ROSETTE_S2_r5\';
File = 'ROSETTE_S2_r5_GeometricData.csv';
FF = fullfile(IdlCatalogue_Dir,File);
Type = strrep(File, '_GeometricData_TOT.csv', '');
Type = strrep(Type,'_','\_');
data = load(FF);
deq = data(end-199:end,16);
for i=1:length(deq)
minimum(i)=min(deq(1:i));
% i'th of maximum would be the max upto ith interval of deq .
end
x=1:1:200;
figure()
plot(x,maximum);
hold on;
plot(x,minimum); set(gca,'xscale','log');
xlabel('number of projections')
ylabel('Deq(µm)')
title('Variation of Max Deq and Min Deq with number of projections')

Iniciar sesión para comentar.


jonas
jonas el 28 de Mayo de 2018
Perhaps this will help...
data=readtable('ROSETTE_S2_R5_GeometricData.csv');
[volumes]=unique(data{:,1});
out=nan(2,length(volumes));
for i=1:length(volumes);
out(1,i)=min(data{data{:,1}==volumes(i),16});
out(2,i)=max(data{data{:,1}==volumes(i),16});
end
figure;
plot(volumes,out(1,:),...
volumes,out(2,:));
  9 comentarios
sud
sud el 28 de Mayo de 2018
hi. so sorry for the bad format but i did try to select it and code it. i dont know why is it not taking the form of code!
jonas
jonas el 28 de Mayo de 2018
I did some formatting and wrote this for you (see attached). All values are stored in maximum and minimum. You can choose which curve to plot by changing the variable id.
If you need anything else, please format the post correctly.

Iniciar sesión para comentar.

Categorías

Más información sobre Numerical Integration and Differential Equations en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by